Integrand size = 24, antiderivative size = 49 \[ \int \frac {(b d+2 c d x)^2}{a+b x+c x^2} \, dx=2 d^2 (b+2 c x)-2 \sqrt {b^2-4 a c} d^2 \text {arctanh}\left (\frac {b+2 c x}{\sqrt {b^2-4 a c}}\right ) \]
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Time = 0.02 (sec) , antiderivative size = 49, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.125, Rules used = {706, 632, 212} \[ \int \frac {(b d+2 c d x)^2}{a+b x+c x^2} \, dx=2 d^2 (b+2 c x)-2 d^2 \sqrt {b^2-4 a c} \text {arctanh}\left (\frac {b+2 c x}{\sqrt {b^2-4 a c}}\right ) \]
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Rule 212
Rule 632
Rule 706
Rubi steps \begin{align*} \text {integral}& = 2 d^2 (b+2 c x)+\left (\left (b^2-4 a c\right ) d^2\right ) \int \frac {1}{a+b x+c x^2} \, dx \\ & = 2 d^2 (b+2 c x)-\left (2 \left (b^2-4 a c\right ) d^2\right ) \text {Subst}\left (\int \frac {1}{b^2-4 a c-x^2} \, dx,x,b+2 c x\right ) \\ & = 2 d^2 (b+2 c x)-2 \sqrt {b^2-4 a c} d^2 \tanh ^{-1}\left (\frac {b+2 c x}{\sqrt {b^2-4 a c}}\right ) \\ \end{align*}
Time = 0.03 (sec) , antiderivative size = 47, normalized size of antiderivative = 0.96 \[ \int \frac {(b d+2 c d x)^2}{a+b x+c x^2} \, dx=d^2 \left (4 c x-2 \sqrt {-b^2+4 a c} \arctan \left (\frac {b+2 c x}{\sqrt {-b^2+4 a c}}\right )\right ) \]
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Time = 2.63 (sec) , antiderivative size = 52, normalized size of antiderivative = 1.06
method | result | size |
default | \(d^{2} \left (4 c x +\frac {2 \left (-4 a c +b^{2}\right ) \arctan \left (\frac {2 c x +b}{\sqrt {4 a c -b^{2}}}\right )}{\sqrt {4 a c -b^{2}}}\right )\) | \(52\) |
risch | \(4 c \,d^{2} x +\sqrt {-4 a c +b^{2}}\, d^{2} \ln \left (-2 \sqrt {-4 a c +b^{2}}\, c x -\sqrt {-4 a c +b^{2}}\, b -4 a c +b^{2}\right )-\sqrt {-4 a c +b^{2}}\, d^{2} \ln \left (2 \sqrt {-4 a c +b^{2}}\, c x +\sqrt {-4 a c +b^{2}}\, b -4 a c +b^{2}\right )\) | \(109\) |
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Time = 0.28 (sec) , antiderivative size = 132, normalized size of antiderivative = 2.69 \[ \int \frac {(b d+2 c d x)^2}{a+b x+c x^2} \, dx=\left [4 \, c d^{2} x + \sqrt {b^{2} - 4 \, a c} d^{2} \log \left (\frac {2 \, c^{2} x^{2} + 2 \, b c x + b^{2} - 2 \, a c - \sqrt {b^{2} - 4 \, a c} {\left (2 \, c x + b\right )}}{c x^{2} + b x + a}\right ), 4 \, c d^{2} x - 2 \, \sqrt {-b^{2} + 4 \, a c} d^{2} \arctan \left (-\frac {\sqrt {-b^{2} + 4 \, a c} {\left (2 \, c x + b\right )}}{b^{2} - 4 \, a c}\right )\right ] \]
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Leaf count of result is larger than twice the leaf count of optimal. 99 vs. \(2 (48) = 96\).
Time = 0.22 (sec) , antiderivative size = 99, normalized size of antiderivative = 2.02 \[ \int \frac {(b d+2 c d x)^2}{a+b x+c x^2} \, dx=4 c d^{2} x + d^{2} \sqrt {- 4 a c + b^{2}} \log {\left (x + \frac {b d^{2} - d^{2} \sqrt {- 4 a c + b^{2}}}{2 c d^{2}} \right )} - d^{2} \sqrt {- 4 a c + b^{2}} \log {\left (x + \frac {b d^{2} + d^{2} \sqrt {- 4 a c + b^{2}}}{2 c d^{2}} \right )} \]
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Exception generated. \[ \int \frac {(b d+2 c d x)^2}{a+b x+c x^2} \, dx=\text {Exception raised: ValueError} \]
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Time = 0.31 (sec) , antiderivative size = 57, normalized size of antiderivative = 1.16 \[ \int \frac {(b d+2 c d x)^2}{a+b x+c x^2} \, dx=4 \, c d^{2} x + \frac {2 \, {\left (b^{2} d^{2} - 4 \, a c d^{2}\right )} \arctan \left (\frac {2 \, c x + b}{\sqrt {-b^{2} + 4 \, a c}}\right )}{\sqrt {-b^{2} + 4 \, a c}} \]
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Time = 0.07 (sec) , antiderivative size = 81, normalized size of antiderivative = 1.65 \[ \int \frac {(b d+2 c d x)^2}{a+b x+c x^2} \, dx=2\,d^2\,\mathrm {atan}\left (\frac {b\,d^2\,\sqrt {4\,a\,c-b^2}+2\,c\,d^2\,x\,\sqrt {4\,a\,c-b^2}}{b^2\,d^2-4\,a\,c\,d^2}\right )\,\sqrt {4\,a\,c-b^2}+4\,c\,d^2\,x \]
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